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What are the zeros of g(x) = x² + 6x²-3x-54?
OA.
1,2,27
OB.
3,-3, -6
O C. -6.3.6
OD. 2, -1, 18

User Erikfas
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Final answer:

The zeros of the quadratic function g(x) = x² + 6x² - 3x - 54 are 3, -3, and -6.


Step-by-step explanation:

The zeros of a quadratic function are the values of x that make the function equal to zero. To find the zeros of the quadratic function g(x) = x² + 6x² - 3x - 54, we need to solve the equation g(x) = 0.

One way to solve this equation is by factoring. We can rewrite the equation as (x - 3)(x + 6) = 0.

Setting each factor equal to zero, we have x - 3 = 0 and x + 6 = 0. Solving for x gives us x = 3 and x = -6.

Therefore, the correct answer is OB. 3, -3, -6.


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User CamQuest
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