The chemical equation for the reaction between aqueous gold(III) bromide (AuBr3) and solid silver metal (Ag) to produce solid silver bromide (AgBr) and solid gold metal (Au) can be represented as follows:
AuBr3(aq) + 3Ag(s) → 3AgBr(s) + Au(s)
In this reaction:
- Aqueous gold(III) bromide (AuBr3) is a solution of gold(III) ions (Au^3+) and bromide ions (Br^-) in water.
- Solid silver metal (Ag) is in its elemental form.
- Solid silver bromide (AgBr) is a white precipitate that forms when silver ions (Ag^+) react with bromide ions (Br^-).
- Solid gold metal (Au) is produced as a result of the displacement of gold ions by silver metal.
This reaction demonstrates a single displacement or replacement reaction, where silver displaces gold from the gold bromide compound, forming silver bromide and releasing gold in its elemental form.