83.7k views
3 votes
I’ve been stuck on this for an hour. please help me :,)

I’ve been stuck on this for an hour. please help me :,)-example-1
User Tboerman
by
7.6k points

1 Answer

4 votes

Answer:

Equation of parallel line: y = (-3/7)x - 27/7

Equation of perpendicular line: y = (7/3)x + 5/3

Step-by-step explanation

Equation of the line parallel to 3x + 7y = -5 and passing through (-2, -3):

Parallel lines have the same slope. The slope of the original line is -3/7. So, the equation of the parallel line is:

y = (-3/7)x - 27/7

Equation of the line perpendicular to 3x + 7y = -5 and passing through (-2, -3):

Perpendicular lines have slopes that are negative reciprocals. The negative reciprocal of -3/7 is 7/3. So, the equation of the perpendicular line is:

y = (7/3)x + 5/3

User Psyklopz
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories