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4 votes
F(x)=2x

2
+3x−5 and

(

)
=

+
1
g(x)=x+1. Find
(



)
(

)
(f⋅g)(x).

1 Answer

3 votes

Answer:

(f⋅g)(x) = 2x^2 + 7x.

Explanation:

To find the expression for (f⋅g)(x), we need to substitute g(x) into f(x) and simplify the resulting expression.

Given:

f(x) = 2x^2 + 3x - 5

g(x) = x + 1

Step 1: Substitute g(x) into f(x)

(f⋅g)(x) = f(g(x))

Substituting g(x) into f(x), we get:

(f⋅g)(x) = 2(g(x))^2 + 3(g(x)) - 5

Step 2: Substitute g(x) = x + 1 into the expression

(f⋅g)(x) = 2(x + 1)^2 + 3(x + 1) - 5

Step 3: Simplify the expression

Expand (x + 1)^2 using the binomial theorem:

(x + 1)^2 = x^2 + 2x + 1

Substituting this back into the expression, we have:

(f⋅g)(x) = 2(x^2 + 2x + 1) + 3(x + 1) - 5

= 2x^2 + 4x + 2 + 3x + 3 - 5

= 2x^2 + 7x

Therefore, (f⋅g)(x) = 2x^2 + 7x.

User Nick Sabbe
by
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