Answer:Down Below
Explanation:
1. f(x) = (x-1)(x+1)
To dilate this function, we need to multiply it by a constant. Let's choose 2 as the constant:
g(x) = 2(x-1)(x+1)
Now let's sketch the graph of g(x) and identify the zeros:
The graph of g(x) will be similar to f(x), but stretched vertically. The zeros of g(x) will be the same as the zeros of f(x), which are x = -1 and x = 1.
2. h(x) = (x-1)(x+4)
To dilate this function, we'll multiply it by a constant. Let's choose 3 as the constant:
k(x) = 3(x-1)(x+4)
Sketching the graph of k(x) and identifying the zeros:
The graph of k(x) will be similar to h(x), but stretched vertically. The zeros of k(x) will be the same as the zeros of h(x), which are x = -4 and x = 1.
3. g(x) = (2x + 1)(x - 2)
To dilate this function, we'll multiply it by a constant. Let's choose 4 as the constant:
m(x) = 4(2x + 1)(x - 2)
Sketching the graph of m(x) and identifying the zeros:
The graph of m(x) will be similar to g(x), but stretched vertically. The zeros of m(x) will be the same as the zeros of g(x), which are x = -1/2 and x = 2.
4. j(x) = (x-4)(x + 4)
To dilate this function, we'll multiply it by a constant. Let's choose 5 as the constant:
n(x) = 5(x-4)(x + 4)
Sketching the graph of n(x) and identifying the zeros:
The graph of n(x) will be similar to j(x), but stretched vertically. The zeros of n(x) will be the same as the zeros of j(x), which are x = -4 and x = 4.