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The vertices of ADEF are

D(2,5), E(6,3), and
F(4,0).
Graph ADEF and its
image when you translate
ADEF using the vector
<5,−1> .
Graph please

The vertices of ADEF are D(2,5), E(6,3), and F(4,0). Graph ADEF and its image when-example-1

1 Answer

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Answer:Got you

Explanation:

I can describe how to graph the triangle ADEF and its image when translated using the vector <5, -1>, but I cannot create visual graphics. However, I can guide you through the process step by step.

1. Plot the original triangle ADEF using the given coordinates:

- D(2,5)

- E(6,3)

- F(4,0)

2. To graph the translation of the triangle using the vector <5, -1>, you need to add 5 to the x-coordinates and subtract 1 from the y-coordinates of each point.

- The image of point D(2,5) after the translation becomes D'(2+5, 5-1) = D'(7, 4).

- The image of point E(6,3) after the translation becomes E'(6+5, 3-1) = E'(11, 2).

- The image of point F(4,0) after the translation becomes F'(4+5, 0-1) = F'(9, -1).

3. Plot the image triangle A'D'E'F' using the new coordinates you calculated in step 2:

- A'D'(7, 4)

- E'(11, 2)

- F'(9, -1)

Now, you should have the original triangle ADEF and its translated image A'D'E'F'. The image is shifted 5 units to the right (in the positive x-direction) and 1 unit down (in the negative y-direction) from the original triangle.

User Mithuna
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