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what are three possible combinations of two seat tables and 4 seat tables that will seat 140 customers​

User Zork
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To find three possible combinations of two-seat tables and four-seat tables that will seat 140 customers, we need to consider the number of tables of each type that can be used. Let's denote the number of two-seat tables as "x" and the number of four-seat tables as "y".

Combination 1:
Let's assume there are 20 two-seat tables (x = 20) and 20 four-seat tables (y = 20).

Number of customers seated: (20 * 2) + (20 * 4) = 40 + 80 = 120

Combination 2:
Let's assume there are 30 two-seat tables (x = 30) and 10 four-seat tables (y = 10).

Number of customers seated: (30 * 2) + (10 * 4) = 60 + 40 = 100

Combination 3:
Let's assume there are 10 two-seat tables (x = 10) and 25 four-seat tables (y = 25).

Number of customers seated: (10 * 2) + (25 * 4) = 20 + 100 = 120

These are three possible combinations of two-seat tables and four-seat tables that will seat 140 customers.
User Scoopzilla
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