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If 450 are deposited into an account with 8.5 interest rate compounded annually. What is the balance after 9 years?

If 450 are deposited into an account with 8.5 interest rate compounded annually. What-example-1

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Answer:

Explanation:

A = P(1 + r/n)^(nt)

Where:

A is the balance after the given time period,

P is the initial deposit,

r is the interest rate (expressed as a decimal),

n is the number of times the interest is compounded per year, and

t is the number of years.

In this case, the initial deposit is $450, the interest rate is 8.5% (or 0.085), the interest is compounded annually (n = 1), and the time period is 9 years (t = 9).

Substituting these values into the formula, we have:

A = 450(1 + 0.085/1)^(1*9)

Simplifying the expression within the parentheses:

A = 450(1.085)^9

Calculating the value inside the parentheses:

A = 450(1.949005)

Multiplying:

A ≈ 876.552

Therefore, the balance after 9 years will be approximately $876.55

User TonyCool
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