Question

I cant figure out how to relate the problems rogether.

Answer 1

Check the picture below.

we know those two horizontal lines are parallel, so that traverse line is perpendicular to each.

`3y+18~~ = ~~90\implies 3y=72\implies y=\cfrac{72}{3} \implies \boxed{y=24} \\\\[-0.35em] ~\dotfill\\\\ \underset{in~degrees}{\textit{Sum of All Interior Angles}}\\\\ S = 180(n-2) ~~ \begin{cases} n=\stackrel{number~of}{sides}\\[-0.5em] \hrulefill\\ n=4 \end{cases}\implies S=180(4-2)\implies S=360^o \\\\[-0.35em] ~\dotfill`

`(3y+18)+90+(15x+30)+10x~~ = ~~360\implies 3y+25x+138=360 \\\\\\ 3y+25x=122\implies \stackrel{\textit{substituting`