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The following figure shows
\[\triangle ABC\] with side lengths to the nearest tenth.

Find

\[BC\] in

\[\triangle ABC\].
Round to the nearest tenth.


BC=

The following figure shows \[\triangle ABC\] with side lengths to the nearest tenth-example-1

1 Answer

4 votes

Answer :

  • 10.8

Task :

  • To work out the measure of side BC

Solution :

According to the law of sines, the ratio of the length of a side to the sine of the angle opposite to it in a triangle is equal for all the sides and angles in the respective triangle.

The law of sines is given by ,


  • (a)/( \sin(a) ) = (b)/( \sin(b) ) \\

wherein,

  • a and b = sides of the triangle
  • sin(a) = angle opposite to side a
  • sin(b) = angle opposite to side b

comparing ,

  • a = BC
  • b = 16
  • sin(b) = 180° - (39° + 42°) = 99°
  • sin(a) = 42°

plugging in the values in the formula,


  • (16)/( \sin(99) ) = (a)/( \sin(42) ) \\

  • (16)/(0.987) = (a)/(0.699) \\

  • 0.987a = 16 * 0.669

  • a = (10.704)/(0.987) \\

  • a = 10.8

Thus, the measure of BC is 10.8 .

User Jacob Griffin
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