69.4k views
5 votes
Challenge The price of Stock A at 9 A.M. was ​$12.52. Since​ then, the price has been increasing at the rate of ​$0.11 each hour. At noon the price of Stock B was ​$13.02. It begins to decrease at the rate of ​$0.14 each hour. If the two rates​ continue, in how many hours will the prices of the two stocks be the​ same

User Mlowton
by
8.1k points

1 Answer

5 votes

Answer:

0.68 hours

Explanation:

Noon is 12:00 P.M., which is 3 hours after 9 A.M., 3*0.11=0.33, so we will add $0.33 to $12.52, getting $12.85.

We will use these steps to get an equation:
1. 12.85 - stock A at 12:00.

2. x - # of hours

3. x(0.11) - the amount of money gained in x hours

4. 12.85+x(0.11) - stock price after x hours

5. 13.02 - stock B at 12:00

6. x - # of hours (this will be the same as we are looking for the amount of time it will take for them to be equal, making this also equal.

7. x(-0.14) - the amount of money Decreased in x hours, which is why it is -0.14

8. 13.02+x(-0.14) - stock price after x hours
9. 12.85+x(0.11)=13.02+x(-0.14) - the final equation after combining them

Solving the equation gives the answer of 0.68 hours

User Lorenzo Isidori
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories