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A 0.30-m radius car tire rotates how many rad after starting from rest and accelerating at a constant 3.0 rad sa

over a 5.0-s interval?​

1 Answer

3 votes

Answer:

The angular displacement is 37.5 radian.

Step-by-step explanation:

Given that,

The radius of the car, r = 0.3 m

The acceleration of the car,
\alpha =3\ rad/s^2

The initial speed of the car,
\omega_i=0

Time, t = 5 s

The angular displacement can be calculated using second equation of motion i.e.


\theta=\omega_it+(1)/(2)\alpha t^2\\\\\theta=(1)/(2)\alpha t^2\\\\\theta=(1)/(2)* 3* (5)^2\\\\\theta=37.5\ rad

So, it will make 37.5 radians.

User Joe Lyga
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