84.8k views
4 votes
Find the slope of the tangent line to the curve 6sin(x) + 5cos(y) - 2sin(x)cos(y) = 6π at the point (6π, (3π)/2).

User Guzba
by
7.0k points

1 Answer

1 vote

To solve this problem, let's follow these steps:

Step 1: Identify the curve and the point

The curve in question is given by the function:

f(x, y) = 6sin(x) + 5cos(y) - 2sin(x)cos(y) = 6π

The point at which we're wanting to find the slope is (6π, (3π)/2).

Step 2: Compute the derivative

We will take the derivative of the curve function with respect to x:

f'(x, y) = df/dx = -2cos(x)cos(y) + 6cos(x)

This derivative function tells us the slope of the tangent line to any point on the curve.

Step 3: Evaluate the derivative at the point

Now, we want to find the slope of the curve at a particular point, (6π, (3π)/2). Plug x = 6π and y = (3π)/2 into the derivative function:

f'(6π, (3π)/2) = -2cos(6π)cos((3π)/2) + 6cos(6π) = 6

So, the slope of the tangent line to the curve at the point (6π, (3π)/2) is 6.

User Thegreatjedi
by
6.7k points