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∆ABC is an isosceles triangle. The length of base BC is 16. AB = AC =9, then length of the altitude AD = A √17B √14C √337D √65​?

User Jay Taylor
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Answer:

Step-by-step explanation:To find the length of the altitude AD in an isosceles triangle, we can use the Pythagorean Theorem.

Given:

Base BC = 16

Sides AB = AC = 9

Step 1: Draw the altitude AD from vertex A to base BC.

Step 2: Since triangle ABC is isosceles, AD will be the perpendicular bisector of base BC.

Step 3: The length of the altitude AD can be found by using the Pythagorean Theorem in triangle ABD or triangle ACD.

In triangle ABD:

AB² = AD² + BD²

(9)² = AD² + (8)²

81 = AD² + 64

AD² = 81 - 64

AD² = 17

AD = √17

In triangle ACD:

AC² = AD² + CD²

(9)² = AD² + (8)²

81 = AD² + 64

AD² = 81 - 64

AD² = 17

AD = √17

Since both triangle ABD and triangle ACD yield AD = √17, we can conclude that the length of the altitude AD in triangle ABC is √17.

User Alswl
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