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Find the slope of the line through point B(-3,6) perpendicular to line AC, where A(-3,2) and C(-1,6).

User Kimchy
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1 Answer

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Firstly, let's understand that the slope of a line is a measure of the vertical change (rise) for each unit of horizontal change (run). The formula for calculating the slope of a line connecting two points `A(x1, y1)` and `B(x2, y2)` is given by `(y2 - y1) / (x2 - x1)`.

Using this formula, we can find the slope of the line between the points A(-3,2) and C(-1,6). Subtract the `y` coordinates of point A from point C to calculate the 'rise' (i.e. 6 - 2 = 4 ). Then, subtract the `x` coordinates of point A from point C to calculate the 'run' (i.e. -1 - (-3) = 2). By dividing the rise by the run, we find that the slope of line AC is 2.

Next, recall that the slope of a line perpendicular to a given line is the negative reciprocal of the original line's slope. By finding the negative reciprocal of the slope of line AC (which is 2), we obtain -1/2. This means that the slope of the line passing through point B and perpendicular to line AC is -0.5.

In conclusion, the slope of line AC is 2 and the slope of the line through point B that is perpendicular to line AC is -0.5.

User Yuvraj Kakkar
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