132k views
2 votes
Find the slope of the line through point B(-3,6) perpendicular to line AC, where A(-3,2) and C(-1,6).

User Kimchy
by
7.8k points

1 Answer

4 votes

Firstly, let's understand that the slope of a line is a measure of the vertical change (rise) for each unit of horizontal change (run). The formula for calculating the slope of a line connecting two points `A(x1, y1)` and `B(x2, y2)` is given by `(y2 - y1) / (x2 - x1)`.

Using this formula, we can find the slope of the line between the points A(-3,2) and C(-1,6). Subtract the `y` coordinates of point A from point C to calculate the 'rise' (i.e. 6 - 2 = 4 ). Then, subtract the `x` coordinates of point A from point C to calculate the 'run' (i.e. -1 - (-3) = 2). By dividing the rise by the run, we find that the slope of line AC is 2.

Next, recall that the slope of a line perpendicular to a given line is the negative reciprocal of the original line's slope. By finding the negative reciprocal of the slope of line AC (which is 2), we obtain -1/2. This means that the slope of the line passing through point B and perpendicular to line AC is -0.5.

In conclusion, the slope of line AC is 2 and the slope of the line through point B that is perpendicular to line AC is -0.5.

User Yuvraj Kakkar
by
9.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories