Solve x^2+2x+7=0 using the quadratic formula.

asked Jun 5, 2023 106k views

6 votes

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8 votes

Answer:

$x=-1\pm √(6)i$

Explanation:

$x=(-b\pm√(b^2-4ac))/(2a)$

$x=(-(2)\pm√(2^2-4(1)(7)))/(2(1))$

$x=(-2\pm√(4-28))/(2)$

$x=(-2\pm√(-24))/(2)$

$x=(-2\pm√(-1*24))/(2)$

$x=(-2\pm√(-1)√(24))/(2)$

$x=(-2\pm i√(4*6))/(2)$

$x=(-2\pm i√(4)√(6))/(2)$

$x=(-2\pm2i√(6))/(2)$

$x=-1\pm √(6)i$

Richardun answered Jun 9, 2023

5.2k points

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