Question

Solve for x.

5(x-3) + 4(x+3) = 3(x - 1)
Ox=1
0x= -1/2
4
Ox=0
0x = 1/1/2

Answer 1

x = 0

Explanation:

Let's solve for x in the given equation:

5(x - 3) + 4(x + 3) = 3(x - 1)

First, distribute the constants outside the parentheses.

5x - 15 + 4x + 12 = 3x - 3

Now, combine like terms.

(5x + 4x) - 15 + 12 = 3x - 3

9x - 3 = 3x - 3

Next, move the 3x term from the right side to the left side by subtracting 3x from both sides of the equation.

9x - 3x - 3 = -3

6x - 3 = -3

Now, add 3 to both sides of the equation to isolate the x term:

6x - 3 + 3 = -3 + 3

6x = 0

Finally, divide both sides by 6 to solve for x:

(6x)/6 = 0/6

x = 0

Answer 2

x=0

Explanation:

Solve for x.

5(x-3) + 4(x+3) = 3(x - 1)

Distribute:

5(x)-5(3) + 4(x)+4(3) = 3(x) -3(1)

5x -15+4x +12 = 3x -3

Combine like terms.

9x -3 = 3x-3

Add 3 to each side

9x-3+3 = 3x-3+3

9x =3x

Subtract 3x from each side

9x-3x =0

6x =0

x=0