Final answer:
The zeros of the function f(x) = 2x² + 18x + 33.8 are approximately -3.68 and -4.82.
Step-by-step explanation:
To find the zeros of the function f(x) = 2x² + 18x + 33.8, we need to solve the equation 2x² + 18x + 33.8 = 0. We can use the quadratic formula, which states that the solutions for any quadratic equation ax² + bx + c = 0 can be found using the formula: x = (-b ± sqrt(b² - 4ac)) / (2a).
For the given equation, a = 2, b = 18, and c = 33.8. Plugging these values into the quadratic formula, we get:
x = (-18 ± sqrt(18² - 4(2)(33.8))) / (2(2))
Simplifying this, we find the two zeros of the function to be approximately -3.68 and -4.82, rounded to the nearest hundredth.
Learn more about Finding zeros of a quadratic function