Question

There are 3 consecutive integers twice the first is 20 more than the second. Find the

smallest number.
23
22
24
21

Answer 1

The smallest number among three consecutive integers is 21.

Step-by-step explanation:

Let the three consecutive integers be x, x+1, and x+2.

According to the given statement, twice the first integer (2x) is 20 more than the second integer (x+1).

So, we can set up the equation 2x = (x+1) + 20 and solve for x.

Simplifying this equation, we get x = 21.

Therefore, the smallest number among the three consecutive integers is 21.

Learn more about Finding the smallest number in a sequence of consecutive integers