Question

How to solve 2(q+4)=16how to solve 7j+2=12+5jhow to solve 12z=60-3z

Answer 1

Given that to solve

a) 2(q+4)=16

we get,

`\begin{gathered} 2\mleft(q+4\mright)=16 \\ 2q+8=16 \end{gathered}`
`2q=16-8`
`2q=8`

Dividing 2 on both sides we get,

`q=4`

Answer is: q=4

b)7j+2=12+5j

we get,

`7j+2=12+5j`
`7j-5j=12-2`
`2j=10`

Dividing 2 on both sides, we get

`j=10`

c) 12z=60-3z

we get,

`12z=60-3z`
`12z+3z=60`
`15z=60`

Dividing 15 on both sides we get,

`z=4`