Answer:
To determine the grams of triethylamine needed to make a 0.20 M solution, we need to use the formula:
Molarity (M) = moles of solute / liters of solution
Given that the desired volume of the solution is 10.0 mL (or 0.010 L) and the desired molarity is 0.20 M, we can rearrange the formula to solve for moles of solute:
moles of solute = Molarity (M) * liters of solution
moles of solute = 0.20 M * 0.010 L = 0.002 moles
To convert moles of triethylamine to grams, we need to know its molar mass. The molar mass of triethylamine (C6H15N) is 101.19 g/mol.
grams of triethylamine = moles of solute * molar mass
grams of triethylamine = 0.002 moles * 101.19 g/mol = 0.20238 grams
Therefore, to make a 10.0 mL of a 0.20 M solution of triethylamine, you would need approximately 0.20238 grams of triethylamine.
Step-by-step explanation: