Answer:
To determine the number of grams of oxygen in 20.0 g of sucrose, we need to calculate the mass of oxygen in the given amount of sucrose.
Given that sucrose is 51.50% oxygen, we can assume that 100 g of sucrose contains 51.50 g of oxygen.
To find the mass of oxygen in 20.0 g of sucrose, we can set up a proportion:
(51.50 g of oxygen) / (100 g of sucrose) = (x g of oxygen) / (20.0 g of sucrose)
Cross-multiplying, we get:
(51.50 g of oxygen) * (20.0 g of sucrose) = (100 g of sucrose) * (x g of oxygen)
1030 g·g = 100x
Dividing both sides by 100, we find:
10.30 g = x
Therefore, there are 10.30 grams of oxygen in 20.0 grams of sucrose.
Step-by-step explanation: