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How many grams of LiF would be present in 575 mL of 0.750 M LiF solution

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Answer: 11.19 g LiF

Explanation: First, convert 575 mL to L by dividing 575 by 1000, as there are 1000 mL in a L, to get 0.575 L.

Since M is mol/L, you can multiply 0.750 M by 0.575 to cancel out the L units to get 0.4313 mol LiF.

Finally, to convert this to grams of LiF, multiply 0.4313 mol LiF, by the molar mass of LiF, which is 25.94. This will give you 11.19 g LiF

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