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Y^3+x^2y=16 find dy/dx

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Answer:

To find the derivative of y with respect to x, we can use implicit differentiation. First, we differentiate both sides of the equation with respect to x:

3y^2(dy/dx) + 2xy + x^2(dy/dx) = 0

Next, we can solve for dy/dx:

dy/dx = -2xy / (3y^2 + x^2)

Therefore, the derivative of y with respect to x is -2xy / (3y^2 + x^2).

I hope this helps!

User TheSeeker
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