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Suppose f(x) is a function such that if p

User Cory Nezin
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1 Answer

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Answer: -f(x) can be odd but cannot be even.

Explanation:

we are given that for any p<q

f(p)<f(q)

this clearly implies that f is an increasing function.

Now we know that if f is an increasing function then -f is always an decreasing function and vice-versa.

so here -f(x) will be an decreasing function.

Let us consider a example f(x)=x then f(x) is clearly an increasing function.

and -f(x)= -x is an decreasing function. also it is an odd function but not an even function.

User Tom Hartman
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