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20. Passes through (-7, -3) and (5, 6)

User Mert Celik
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Answer:

The equation of the line that passes through the points (-7, -3) and (5, 6) is y = (3/4)x + 9/4.

Explanation:

To find the equation of a line that passes through the points (-7, -3) and (5, 6), we can use the slope-intercept form of a linear equation, which is y = mx + b. In this form, m represents the slope of the line, and b represents the y-intercept.

Step 1: Find the slope (m) of the line using the formula:

m = (y2 - y1) / (x2 - x1)

Substituting the coordinates (-7, -3) and (5, 6) into the formula, we get:

m = (6 - (-3)) / (5 - (-7))

m = 9 / 12

m = 3/4

Step 2: Use one of the points and the slope to find the value of b in the equation y = mx + b. Let's use the point (-7, -3):

-3 = (3/4)(-7) + b

-3 = -21/4 + b

To find b, we can add 21/4 to both sides of the equation:

-3 + 21/4 = b

-12/4 + 21/4 = b

9/4 = b

Step 3: Write the equation of the line using the slope (m) and the y-intercept (b):

y = (3/4)x + 9/4

Therefore, the equation of the line that passes through the points (-7, -3) and (5, 6) is y = (3/4)x + 9/4.

User Pedjjj
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