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What is the equation of the line that passes through the point (−2,−5) and has a slope of minus, -3/2

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Answer:y = (-3/2)x - 8.

Step-by-step explanation: Given the point (-2, -5) and the slope -3/2, we can plug these values into the equation to find the specific equation of the line.

First, let's find the y-intercept, b. We can use the point (-2, -5) in the equation.

-5 = (-3/2)(-2) + b

Simplify:

-5 = 3 + b

Now solve for b:

b = -5 - 3 = -8

Now we have the slope (m = -3/2) and the y-intercept (b = -8). Thus, the equation of the line is:

y = (-3/2)x - 8.

User Maetl
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