Question

What is an object's final velocity if it has an initial velocity of +12 meters/second with a constant acceleration of +14 meters/second2 and has traveled 48 meters in the +x direction?

Answer 1

To solve this problem, we can use the following equation of motion:

```
vf^2 = vi^2 + 2as
```

where:

* vf is the final velocity
* vi is the initial velocity
* a is the acceleration
* s is the distance traveled

Substituting the given values, we get:

```
vf^2 = 12^2 + 2 * 14 * 48
vf^2 = 880
vf = 29.6 m/s
```

Therefore, the object's final velocity is **29.6 m/s**.

**Answer:** 29.6 m/s