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What is the pOH of a solution at 25.0∘C with [OH−]=2.7×10−2 M?

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Final answer:

The pOH of a solution at 25.0∘C with [OH−]=2.7×10−2 M is calculated to be 1.57 by using the formula pOH = -log [OH−]. As the pOH is below 7, the solution is basic.

Step-by-step explanation:

The pOH of a solution is calculated using the formula pOH = -log [OH−]. The student's question involves a solution at 25.0∘C with a hydroxide ion concentration ([OH−]) of 2.7×10−2 M.

To calculate the pOH, we substitute the given [OH−] into the formula: pOH = -log (2.7×10−2). This gives pOH = 1.57 (rounded to 2 decimal places).

This indicates the solution is basic because the pOH is less than 7. In general, at 25.0∘C, a neutral solution will have pOH (and pH) equal to 7. A solution is considered acidic if pOH > 7 and basic if pOH < 7.

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