To find the equation of a line perpendicular to y = 2x + 7, we need to determine the negative reciprocal of the slope of the given line.
The slope of y = 2x + 7 is 2.
The negative reciprocal of 2 is -1/2.
Now, we can use the point-slope form of a line to find the equation.
Using the point (6, 3) and the slope -1/2, the equation of the line in slope-intercept form is:
y - 3 = (-1/2)(x - 6)
Simplifying the equation:
y - 3 = (-1/2)x + 3
y = (-1/2)x + 6
Therefore, the equation of the line that passes through the point (6, 3) and is perpendicular to y = 2x + 7 is y = (-1/2)x + 6.