Final answer:
To determine the number of grams of NaNO3 in a 1.0 M solution with a volume of 500 mL, we can use the formula Moles = Molarity x Volume. Converting the volume to liters and plugging the values into the formula allows us to calculate the moles of NaNO3, which can then be converted to grams using the molar mass of NaNO3. The result is 42.5 grams of NaNO3 in the solution.
Step-by-step explanation:
To determine the number of grams of NaNO3 in the solution, we need to use the formula:
Moles = Molarity x Volume
First, we convert the volume from mL to L by dividing it by 1000:
500 mL = 500/1000 L = 0.5 L
Then, we can plug the values into the formula:
Moles = 1.0 M x 0.5 L = 0.5 mol
Finally, we can use the molar mass of NaNO3 (85.0 g/mol) to convert moles to grams:
Grams = Moles x Molar mass
Grams = 0.5 mol x 85.0 g/mol = 42.5 g
Therefore, there are 42.5 grams of NaNO3 present in the 500 mL of the 1.0 M solution.
Learn more about Calculating grams of a compound in a given volume of solution