Question

Solve the following simulataneous equations using an algebraic method (not graphical).

2x + 5y = 0
3x-4y = 23

Answer 1

Given:

The equations are

`2x+5y=0`

`3x-4y=23`

To find:

The solution of given system of equations.

Solution:

We have,

`2x+5y=0` ...(i)

`3x-4y=23` ...(ii)

From (i), we get

`2x=-5y`

`x=-(5y)/(2)` ...(iii)

Putting this value in (ii), we get

`3(-(5y)/(2))-4y=23`

`-(15y)/(2)-4y=23`

`(-15y-8y)/(2)=23`

`-23y=2* 23`

`y=(46)/(-23)`

`y=-2`

Putting y=-2 in (iii), we get

`x=-(5(-2))/(2)`

`x=-(-10)/(2)`

`x=(10)/(2)`

`x=5`

Therefore, the solution of given system of equation is (5,-2).