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Find the length of a rectangle that has a diagonal of 55 feet and a width of 27 feet. Round to two

decimal places.

User Saber
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Final answer:

The length of the rectangle is approximately 47.93 feet.


Step-by-step explanation:

The length of a rectangle can be found using the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the other two sides. In this case, the diagonal of the rectangle is the hypotenuse, and the width and length are the other two sides. So, we can use the formula d^2 = w^2 + l^2, where d is the length of the diagonal, w is the width, and l is the length. Rearranging the formula, we have l^2 = d^2 - w^2. Plugging in the given values, we get l^2 = 55^2 - 27^2 = 3025 - 729 = 2296. Taking the square root of both sides, we find l ≈ 47.93 feet. Therefore, the length of the rectangle is approximately 47.93 feet.

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User Dwestgate
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