338,725 views
3 votes
3 votes
i need help with this HW problem it is ,the length of a rectangle is 2 more thn 3 times the width.If the perimeter is 46 ,si what would the length and width be?

User BadSkillz
by
2.9k points

1 Answer

16 votes
16 votes

If w is the width of the rectangle, then, you have for the length l of the rectangle:

l = 3w + 2

take into account that the perimeter of the rectangle is 46, and the expresionf for the perimeter P is:

P = 2l + 2w

in order to determine the value of the length l, replace the expression

l = 3w + 2 into the expression for the perimeter P, then, solve for w:

P = 2(3w + 2) + 2w

P = 6w + 4 + 2w

P = 8w + 4

replace P = 46:

46 = 8w + 4

46 - 4 = 8w

42 = 8w

42/8 = w

21/4 = w

5.25 = w

replace the previous value of w into the expression l = 3w + 2

l = 3(5.25) + 2

l = 17.75

Hence, the length of the rectangle is 17.75

User OddNorg
by
2.9k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.