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What is the area of a rectangle with vertices at (4, 3), (11, 3), (11,9), and (4,

9)?
OA. 21 units²
OB. 26 units²
O C. 13 units²
OD. 42 units²

User Sarkhan
by
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1 Answer

1 vote

Answer:

AI-generated answer

To find the area of a rectangle, we need to multiply its length by its width.

In this case, the rectangle has vertices at (4, 3), (11, 3), (11, 9), and (4, 9).

To find the length, we can calculate the difference between the x-coordinates of two adjacent vertices. The x-coordinate of the first vertex (4, 3) and the x-coordinate of the second vertex (11, 3) are both 4. So, the length of the rectangle is 11 - 4 = 7 units.

To find the width, we can calculate the difference between the y-coordinates of two adjacent vertices. The y-coordinate of the first vertex (4, 3) and the y-coordinate of the fourth vertex (4, 9) are both 3. So, the width of the rectangle is 9 - 3 = 6 units.

Now, we can calculate the area by multiplying the length by the width:

Area = length × width = 7 units × 6 units = 42 units².

Therefore, the correct answer is option OD: 42 units².

Explanation:

User Cce
by
7.4k points