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Question 2 of 40

What is a point-slope equation of the line with slope -12 that goes through
the point (5, 3)?
O A. y+3= 12(x + 5)
B. y+ 3 = -12(x+5)
OC. y-3--12(x - 5)
OD.y-3= 12(x - 5)
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Answer:

The point-slope form of a linear equation is given by y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope of the line.

In this case, the slope is -12 and the point (5, 3) lies on the line.

Using the point-slope form, we can substitute the values into the equation:

y - 3 = -12(x - 5)

Therefore, the point-slope equation of the line with slope -12 that goes through the point (5, 3) is:

y - 3 = -12(x - 5)

So, the correct answer is option B: y + 3 = -12(x + 5).

Explanation:

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