Question

4. A bird accelerates from rest at a rate of 3.7 m/s2 for 2.4 seconds. How far has the

bird traveled during this time?

Answer 1

Step-by-step explanation:

Find the acceleration

chnage in v / change in time = 3.7 m/s / 2.4 s = 1.541 m/s^2

THEN

df = vot + 1/2 a t^2

= 0 + 1/2 (1.541) ( 2.4)^2 = 4.44 m