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A line has a slope of 2 and passes through the point (-12,-16). write its equation in slope intercept form.

User Vibhas
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To write the equation of a line in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept, we need to substitute the given values into the equation.

Given:
Slope (m) = 2
Point on the line: (-12, -16)

We can substitute the slope (m) and the coordinates of the point (x, y) into the equation and solve for the y-intercept (b).

y = mx + b
-16 = 2(-12) + b
-16 = -24 + b

To isolate b, we add 24 to both sides of the equation:

-16 + 24 = -24 + b + 24
8 = b

Now we have the value of the y-intercept (b), which is 8.

The equation of the line in slope-intercept form is:

y = 2x + 8
User RBRi
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