Question

Question 10 of 10

What is the pOH of a solution with [OH-] = 9.0 × 10-7?
OA. -7.00
OB. 6.04
C. 7.95
O D. 9.54

Answer 1

The pOH of a solution with [OH-] = 9.0 × 10-7 is 6.046.

Step-by-step explanation:

The pOH of a solution can be calculated using the formula:
pOH = -log[OH-]

Given that [OH-] = 9.0 × 10-7, we can substitute this value into the formula:
pOH = -log(9.0 × 10-7)

Simplifying the expression:
pOH = -log(9.0) - log(10-7)
pOH = -0.954 - (-7)
pOH = -0.954 + 7

Final calculation gives:
pOH = 6.046

Therefore, the pOH of the solution is 6.046.

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