Answer:
At point P, the net electric field is zero.
Step-by-step explanation:
In this scenario, you have two point charges, q1 and q2, arranged in a line with point P. Charge q1 is located 0.10 meters to the left of point P, and charge q2 is located 0.10 meters to the right of point P. Both charges have a magnitude of 12 x 10^(-6) C, but q1 is negative, and q2 is positive.
To determine the net electric field at point P, you can calculate the electric fields created by each charge individually and then add them together. The electric field created by a point charge can be calculated using Coulomb's law:
Electric field (E) = (k * |q|) / r^2
Where:
- k is Coulomb's constant, approximately 8.99 x 10^9 N m²/C².
- |q| is the magnitude of the charge.
- r is the distance from the charge to the point where you want to find the electric field.
For point P, you have two charges, so you'll calculate the electric field created by each charge separately and then add them vectorially (considering direction). The electric field due to q1 points to the left, and the electric field due to q2 points to the right. Since they have the same magnitude, they will cancel each other out because they are in opposite directions.
So, at point P, the net electric field is zero.
Here's a simple diagram to illustrate the situation:
```
q1 (-) P q2 (+)
←----→
```
The arrows represent the direction of the electric fields created by q1 and q2. Since they are equal in magnitude but opposite in direction, they cancel out at point P, resulting in a net electric field of zero.