Question

The height h, in feet, of a ball above the ground t seconds after being thrown upward with a velocity of 64 ft/s is given by h -16² +64t + 5. After how many seconds will the ball be 53 ft above the

ground?

Answer 1

To find the time it takes for the ball to be 53 ft above the ground, set the height equation equal to 53 ft and solve for t to get t ≈ 3 seconds.

Step-by-step explanation:

To find the time it takes for the ball to be 53 ft above the ground, we set the height equation h = -16t^2 + 64t + 5 equal to 53 ft and solve for t.

-16t^2 + 64t + 5 = 53

-16t^2 + 64t - 48 = 0

Simplifying further gives us -t^2 + 4t - 3 = 0

Using the quadratic formula, t = (-b ± sqrt(b^2 - 4ac))/(2a), where a=-1, b=4, and c=-3, we can solve for t.

Plugging in the values, we get t ≈ 3 seconds as the time it takes for the ball to be 53 ft above the ground.

Learn more about Calculating time for the ball to reach a certain height