139k views
0 votes
RRCM 4 5. If y= 2x²-x, find the value of x for which dy dx = 0 (A) 0, + 1/1/2 (C) 0, +-1/ (B) 1, ± -IN 2 (D) None of these​

User Jyr
by
7.6k points

1 Answer

5 votes

Step-by-step explanation:

To find the value of x for which dy/dx = 0 for the given function y = 2x² - x, you need to calculate the derivative of y with respect to x and then set it equal to 0.

First, calculate the derivative dy/dx:

dy/dx = d/dx(2x² - x)

dy/dx = 4x - 1

Now, set dy/dx equal to 0 and solve for x:

0 = 4x - 1

4x = 1

x = 1/4

So, the value of x for which dy/dx = 0 is x = 1/4.

The correct option is (B) 1, ± -1/4.

User ZarNi Myo Sett Win
by
8.5k points