Question

For g(x)=2x2−8x−10, find each value g(2) g(2) drop zone empty. g(5)+12 g(5)+12 drop zone empty. g(8)–18 g(8)–18 drop zone empty. g(–3)–g(4) g(–3)–g(4) drop zone empty. 18 36 12 –12 –18 –36 42 –42

Answer 1

-18 (drop zone empty)

12 (drop zone empty)

36 (drop zone empty)

42 (drop zone empty)

Explanation:

To find the values of g(2), g(5), g(8), g(-3), and g(4), you simply need to substitute these values into the function g(x) = 2x^2 - 8x - 10. Let's calculate them one by one:

g(2):

g(2) = 2(2)^2 - 8(2) - 10

g(2) = 2(4) - 16 - 10

g(2) = 8 - 16 - 10

g(2) = -8 - 10

g(2) = -18

g(5):

g(5) = 2(5)^2 - 8(5) - 10

g(5) = 2(25) - 40 - 10

g(5) = 50 - 40 - 10

g(5) = 10 - 10

g(5) = 0

g(8):

g(8) = 2(8)^2 - 8(8) - 10

g(8) = 2(64) - 64 - 10

g(8) = 128 - 64 - 10

g(8) = 128 - 74

g(8) = 54

g(-3):

g(-3) = 2(-3)^2 - 8(-3) - 10

g(-3) = 2(9) + 24 - 10

g(-3) = 18 + 24 - 10

g(-3) = 42 - 10

g(-3) = 32

g(4):

g(4) = 2(4)^2 - 8(4) - 10

g(4) = 2(16) - 32 - 10

g(4) = 32 - 32 - 10

g(4) = 0 - 10

g(4) = -10

Now, let's evaluate the expressions you provided:

g(5) + 12 = 0 + 12 = 12

g(8) - 18 = 54 - 18 = 36

g(-3) - g(4) = 32 - (-10) = 32 + 10 = 42

The values are as follows:

g(2) = -18

g(5) + 12 = 12

g(8) - 18 = 36

g(-3) - g(4) = 42

So, the correct answers are:

-18 (drop zone empty)

12 (drop zone empty)

36 (drop zone empty)

42 (drop zone empty)