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Write the equation of the line that has a slope of 1/3 and passes through the point (6,8).

User EversMcc
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1 Answer

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21 votes

We are asked to determine the equation of a line with a slope 1/3. The general form of a line equation is:


y=mx+b

Where "m" is the slope and "b" the y-intercept.

Now, we substitute the value of the slope:


y=(1)/(3)x+b

Now, to determine the value of "b" we will use the fact that the line passes through the point (x, y) = (

6, 8). Now, we plug in these values in the equation:


8=(1)/(3)(6)+b

Solving the product on the right side we get:


8=2+b

Now, we subtract 2 from both sides:


\begin{gathered} 8-2=2-2+b \\ 6=b \end{gathered}

Now, we substitute the value in the equation of the line:


y=(1)/(3)x+6

And thus we get the equation of the line.

User Geena
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