Question

Please help

find molecular formula of a compound with a molar mass of 45.0 g/mol and an empirical formula of CH3

Answer 1

Answer: The molecular formula will be
`C_3H_9`

Step-by-step explanation:

Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.

The empirical formula is
`CH_3`

The empirical weight of
`CH_3` = 1(12)+3(1)= 15g.

The molecular weight = 45.0 g/mole

Now we have to calculate the molecular formula:

`n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=(45)/(15)=3`

The molecular formula will be=
`3* CH_3=C_3H_9`

Thus molecular formula will be
`C_3H_9`