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Please help me with this question

Please help me with this question-example-1
User Bobtato
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Answer:

Explanation:

sine rules:


\boxed{(a)/(sinA) =(b)/(sinB) =(c)/(sinC) }


(b)/(sinB) =(c)/(sinC)


(29)/(sin\ 21^o) = (33)/(sinC)


sinC=(33(sin\ 21^o))/(29)


=0.4078


C=24^o\ or\ (180-24)^o

Therefore C₁ = 156° and C₂ = 24°

A = 180° - (B + C)

A₁ = 180° - (21 + 156)°

= 3°

A₂ = 180° - (21 + 24)°

= 135°


(b)/(sinB) =(a_1)/(sinA_1)


(29)/(sin\ 21^o) = (a_1)/(sin\ 3^o)


a_1=(29(sin\ 3^o))/(sin\ 21^o)


=4.24


(b)/(sinB) =(a_2)/(sinA_2)


(29)/(sin\ 21^o) = (a_2)/(sin\ 135^o)


a_2=(29(sin\ 135^o))/(sin\ 21^o)


=57.22

User Jeremy Morehouse
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