75.4k views
0 votes
Please help me with this question

Please help me with this question-example-1
User Bobtato
by
8.4k points

1 Answer

1 vote

Answer:

Explanation:

sine rules:


\boxed{(a)/(sinA) =(b)/(sinB) =(c)/(sinC) }


(b)/(sinB) =(c)/(sinC)


(29)/(sin\ 21^o) = (33)/(sinC)


sinC=(33(sin\ 21^o))/(29)


=0.4078


C=24^o\ or\ (180-24)^o

Therefore C₁ = 156° and C₂ = 24°

A = 180° - (B + C)

A₁ = 180° - (21 + 156)°

= 3°

A₂ = 180° - (21 + 24)°

= 135°


(b)/(sinB) =(a_1)/(sinA_1)


(29)/(sin\ 21^o) = (a_1)/(sin\ 3^o)


a_1=(29(sin\ 3^o))/(sin\ 21^o)


=4.24


(b)/(sinB) =(a_2)/(sinA_2)


(29)/(sin\ 21^o) = (a_2)/(sin\ 135^o)


a_2=(29(sin\ 135^o))/(sin\ 21^o)


=57.22

User Jeremy Morehouse
by
8.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories