Answer:
There are approximately 3.317 x 10^23 atoms present in 4.87 mils of palladium (Pd).
Step-by-step explanation:
To determine the number of atoms present in 4.87 mils of palladium (Pd), we need to use the concept of Avogadro's number and molar mass.
Let's break down the steps:
1. Find the molar mass of palladium (Pd) from the periodic table. The molar mass of palladium is approximately 106.42 g/mol.
2. Convert the given quantity of palladium from mils to grams. As 1 mil is equal to 0.001 inches, we need to use the density of palladium to convert mils to grams. Let's assume the density of palladium is 12.023 g/mil³.
Mass of palladium = Volume * Density
Mass of palladium = 4.87 mils * 12.023 g/mil³
Mass of palladium ≈ 58.617 g
3. Use the molar mass of palladium to convert grams of palladium to moles:
Moles of palladium = Mass of palladium / Molar mass
Moles of palladium = 58.617 g / 106.42 g/mol
Moles of palladium ≈ 0.551 moles
4. Finally, use Avogadro's number, which is approximately 6.022 x 10^23 atoms per mole, to convert moles of palladium to atoms:
Number of atoms = Moles of palladium * Avogadro's number
Number of atoms ≈ 0.551 moles * (6.022 x 10^23 atoms/mol)
Number of atoms ≈ 3.317 x 10^23 atoms