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Find the value of a for which a(2x-12)<4(3x-18)-9 has a solution of all real numbers

User Sasensi
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1 Answer

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The first step is to simplify the expression on the right side of the inequality:

4(3x-18)-9 = 12x - 81

Substituting this into the original inequality gives:

a(2x-12) < 12x - 81

Now we can simplify the left side of the inequality:

a(2x-12) = 2ax - 12a

The inequality now reads:

2ax - 12a < 12x - 81

Simplifying, we get:

2ax - 12x < 81 - 12a

Now we can solve for a:

2x(a - 6) < 81 - 12a

2x(a - 6) + 12a - 81 < 0

2ax - 6x - 81 < 0

2x(a - 3) - 3(a - 3) - 81 < 0

(2x - 3)(a - 3) < 81

For this inequality to hold for all real values of x, the left side must be negative, zero, or positive for all x. Since 2x - 3 can take on any real value, we need a - 3 to be such that the product is always less than 81. Thus:

a - 3 < 0

a < 3

Therefore, the value of a that ensures that the inequality has a solution of all real numbers is a < 3.

User SourceVisor
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