113k views
1 vote
Find the value of a for which a(2x-12)<4(3x-18)-9 has a solution of all real numbers

User Sasensi
by
8.1k points

1 Answer

3 votes

The first step is to simplify the expression on the right side of the inequality:

4(3x-18)-9 = 12x - 81

Substituting this into the original inequality gives:

a(2x-12) < 12x - 81

Now we can simplify the left side of the inequality:

a(2x-12) = 2ax - 12a

The inequality now reads:

2ax - 12a < 12x - 81

Simplifying, we get:

2ax - 12x < 81 - 12a

Now we can solve for a:

2x(a - 6) < 81 - 12a

2x(a - 6) + 12a - 81 < 0

2ax - 6x - 81 < 0

2x(a - 3) - 3(a - 3) - 81 < 0

(2x - 3)(a - 3) < 81

For this inequality to hold for all real values of x, the left side must be negative, zero, or positive for all x. Since 2x - 3 can take on any real value, we need a - 3 to be such that the product is always less than 81. Thus:

a - 3 < 0

a < 3

Therefore, the value of a that ensures that the inequality has a solution of all real numbers is a < 3.

User SourceVisor
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories