Answer:
f(x) = (x - 6)(x - 7)
Now, you can expand this expression to obtain the polynomial in standard form:
f(x) = (x - 6)(x - 7)
f(x) = x(x - 7) - 6(x - 7)
Now, distribute and simplify:
f(x) = x(x) - x(7) - 6(x) + 6(7)
f(x) = x^2 - 7x - 6x + 42
Combine like terms:
f(x) = x^2 - 13x + 42
So, the polynomial with roots 6 and 7 is f(x) = x^2 - 13x + 42. This is a polynomial of degree 2 (quadratic) with the given roots.