Answer:
-27x-120xi
Explanation:
(5+4i)^2(3x)
split it into (5+4i)(5+4i)
(25+20i+20i+16i^2)(3x)
(25+40i+16i^2)(3x)
Now, let's find a²b:
a²b = (25 + 40i + 16i²)(-3x)
Since i² is equal to -1, we can simplify further:
a²b = (25 + 40i - 16)(-3x)
a²b = (9 + 40i)(-3x)
Now, multiply the real and imaginary parts separately:
Real part:
9 * (-3x) = -27x
Imaginary part:
40i * (-3x) = -120xi
so a^2b = -27x-120xi